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Q&A about the site for amateur radio enthusiasts

-- Enter Query Title
-- Enter Query Description
SELECT TOP 100 
    Users.Id AS [User Link],
    (CAST(COUNT(a.Id) AS float) / CAST((SELECT COUNT(*) FROM Posts p WHERE p.OwnerUserId = Users.Id AND PostTypeId = 1) AS float) * 100) AS SelfAnswerPercentage
FROM Posts q
    INNER JOIN Posts a ON q.AcceptedAnswerId = a.Id
    INNER JOIN Users ON Users.Id = q.OwnerUserId
WHERE q.OwnerUserId = a.OwnerUserId
GROUP BY Users.Id, DisplayName
HAVING COUNT(a.Id) > 100
ORDER BY SelfAnswerPercentage DESC

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created aug 7 10 anonymous