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Q&A about the site for students, teachers, and linguists wanting to discuss the finer points of the Italian language

-- Enter Query Title
-- Enter Query Description

select
  count(p.Id) as [Count],
  t.TagName   as [Tag]
from
   users    u  inner join
   posts    p  on u.Id = p.OwnerUserId
               inner join
   posttags pt on p.Id = pt.PostId
               inner join
   tags     t  on pt.TagId = t.Id
where p.PostTypeId = 1
group by t.Id, t.TagName
order by count(distinct u.Id) desc;

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created aug 19 10 sth