Stackoverflow #8844796

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with t as (
  select '28 Smith Avenue^MOOROOLBARK VIC 3138^' as str
  union
  select '16 Farr Street^HEYFIELD VIC 3858^' as str
  union
  select '17 Terry Road^LOWER PLENTY VIC 3093^ ' as str
), t1 as (
  select
    str,
    left(str, charindex('^', str) - 1) as address
  from t
)
select 
  str,
  left(str, charindex('^', str) - 1) as Address,
  right(reverse(substring(reverse(str), 2, charindex('^', str))), 4) as Postcode,
  reverse(substring(reverse(str), 2, len(str) - charindex('^', str) - 1))
from t1

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