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Q&A about the site for members of the workforce navigating the professional setting

SELECT TOP(##num?500##)
  RANK() OVER(ORDER BY Count(p.Id) DESC) AS [Rank],
  p.OwnerUserId AS [User Link], p.OwnerDisplayName,
  Count(p.Id) AS [Count],
  SUM(case when p.PostTypeId = 1 then 1 else 0 end) AS QCount,
  SUM(case when p.PostTypeId = 2 then 1 else 0 end) AS ACount
FROM Posts p  
GROUP BY p.OwnerUserId, p.OwnerDisplayName  
ORDER BY Count(p.Id) DESC

fork query

edited feb 20 22

created feb 20 22 Martin20528