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Q&A about the site for members of the workforce navigating the professional setting

-- Temporary table to store the results
CREATE TABLE #results (
  Site NVARCHAR(250),
  Id INT,
  Title NVARCHAR(250),
  ViewCount INT,
  Score INT,
  CreationDate DATETIME
);

-- We'll need (at least) one INSERT statement for each site, they'll end up in this variable
DECLARE @sql NVARCHAR(MAX) = '';

-- Generate INSERT statements:
-- - Use the database's `name` to indicate the site (this can be converted to site name later on)
-- - Fully qualify table names
SELECT @sql = @sql + 'INSERT INTO #results' + N'
SELECT ''' + name + ''', p.Id, p.Title, p.ViewCount, p.Score, p.CreationDate
  FROM ' + QUOTENAME(name) + '.dbo.Posts as p
  INNER JOIN ' + QUOTENAME(name) + '.dbo.Users as u
    ON p.OwnerUserId = u.Id
  WHERE p.PostTypeId = 1
    AND u.AccountId = ' + CAST(##AccountId:int## AS NVARCHAR) + '
'
FROM sys.databases
WHERE database_id > 5; -- that's where the site databases begin
-- AccountId: The global account ID of the user, which you can find in the URL of their network profile. Visit this link: http://stackexchange.com/users/current to see your own ID.

--print @sql

-- execute it
EXEC (@sql);

-- Site details, cf. https://meta.stackexchange.com/a/359795/295232
CREATE TABLE #Sites (URL NVARCHAR(100), SiteName NVARCHAR(100), DatabaseName NVARCHAR(50));
-- fetch Markdown for post containing table with site details
DECLARE @md NVARCHAR(MAX);
SELECT TOP 1 @md = Text
  FROM [StackExchange.Meta].dbo.PostHistory
  WHERE PostId = 359796 AND PostHistoryTypeId = 5
  ORDER BY CreationDate DESC;
-- split Markdown on pipe symbol
CREATE TABLE #TableEntries (ID INT IDENTITY(1, 1), Value NVARCHAR(100));
INSERT INTO #TableEntries (Value)
SELECT LEFT(TRIM(VALUE), 100) FROM STRING_SPLIT(@md, '|')
  WHERE LEN(TRIM(REPLACE(REPLACE(VALUE, CHAR(10), ''), CHAR(13), ''))) > 0;
-- 'pivot' - we have to discard the introductory text, headers and horizontal lines
INSERT INTO #Sites
SELECT t0.Value, t1.Value, t2.Value
  FROM #TableEntries AS t0
  INNER JOIN #TableEntries AS t1
    ON t0.Id + 1 = t1.Id
  INNER JOIN #TableEntries AS t2
    ON t0.Id + 2 = t2.Id
  WHERE t0.Id >= 8 -- that's where the real content starts
    AND t0.Id % 3 = 2;

-- show results
SELECT s.SiteName AS 'Site',
  CONCAT(s.URL, '/q/', r.Id, '|', r.Title) AS 'Question',
  r.ViewCount AS '# views',
  r.Score,
  r.CreationDate AS 'Posted on'
  FROM #Results AS r
  INNER JOIN #Sites AS s
    ON r.Site = s.DatabaseName
  ORDER BY viewcount DESC;

DROP TABLE #results;

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edited apr 11 anonymous

created oct 13 17 Glorfindel