Q&A about the site for members of the workforce navigating the professional setting
-- Overall StackOverflow Reputation, Rank and Percentile WITH Rankings AS ( SELECT Id, Reputation, Ranking = ROW_NUMBER() OVER(ORDER BY Reputation DESC) FROM Users ) ,Counts AS ( SELECT Count = COUNT(*) FROM Users WHERE Reputation > 100 ) SELECT Id, Id as [User Link], Reputation, Ranking, CAST(Ranking AS decimal(20, 5)) / (SELECT Count FROM Counts) AS Percentile FROM Rankings WHERE Id = 4755954