select t.tagname, count (distinct p.owneruserid) as Users...

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select
      t.tagname, count (distinct p.owneruserid) as Users
  from users u, posts p, posttags pt, tags t
  where
        p.owneruserid = u.id
    and p.posttypeid = 2
    and p.score > 0
    and pt.postid=p.ParentId
    and t.id = pt.tagid 
    and (t.tagname='amazon-web-service')
  group by t.tagname

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