Users with high self-accept rates (and having > 10 answers)

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(the extreme self-learners)

Mythology Meta

Q&A about the site for enthusiasts and scholars of mythology and folklore

SELECT 
    TOP 100
    Users.Id AS [User Link],
    (CAST(Count(a.Id) AS float) / CAST((SELECT Count(*) FROM Posts p WHERE p.OwnerUserId = Users.Id AND PostTypeId = 1) AS float) * 100) AS SelfAnswerPercentage
FROM
    Posts q
  INNER JOIN 
    Posts a ON q.AcceptedAnswerId = a.Id
  INNER JOIN
    Users ON Users.Id = q.OwnerUserId
WHERE 
    q.OwnerUserId = a.OwnerUserId
GROUP BY
    Users.Id, DisplayName
HAVING
    Count(a.Id) > 20
ORDER BY
    SelfAnswerPercentage DESC

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