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Q&A for developers and researchers interested in open data

WITH 
  groups(userid, date, grp) AS (
    SELECT DISTINCT
      OwnerUserId,
      CAST(CreationDate AS DATE),
      dateadd(day, 
        -DENSE_RANK() OVER (PARTITION BY OwnerUserId ORDER BY CAST(CreationDate AS DATE)), 
        CAST(CreationDate AS DATE)) AS grp
    FROM Posts
  ),
  max_consecutive_dates AS (
    SELECT 
      userid,
      COUNT(*) AS consecutiveDates,
      MIN(date) AS minDate,
      MAX(date) AS maxDate
    FROM groups
    GROUP BY userid, grp
  )
SELECT 
  userid,
  MAX(consecutiveDates) AS maxConsecutiveDates,
  minDate,
  maxDate
FROM max_consecutive_dates
GROUP BY userid, minDate, maxDate;

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edited feb 27

created nov 7 15 anonymous