Top javascript developers in Egypt.

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SELECT ROW_NUMBER() OVER(ORDER BY Score DESC) AS [#], us.id [User Link],
       us.DisplayName,
       tuser.Score
       
FROM Users us

JOIN 
(SELECT Answers.OwnerUserId AS UserId, SUM(Answers.Score) AS Score
     FROM Tags 
    JOIN PostTags ON Tags.Id = PostTags.TagId
    JOIN Posts ON Posts.Id = PostTags.PostId  
    JOIN Posts Answers ON Answers.ParentId = Posts.Id 
   WHERE Tags.TagName IN ('javascript')
  GROUP BY Answers.OwnerUserId
) tuser ON tuser.UserId = us.Id

WHERE lower(us.Location) like '%egypt%'
ORDER BY Score DESC;

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