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Open Data

Q&A for developers and researchers interested in open data

select u.Id, u.DisplayName, u.Reputation, count(*) as AndroidAnswers from Users u, Posts p, Posts pp where u.Id in (
    select Id
    from Users 
    where Location like ('%Italy')
  and p.OwnerUserId = u.Id
  and pp.Id = p.ParentId
  and pp.Tags like ('%android%')
  group by u.Id,u.DisplayName, u.Reputation
  order by AndroidAnswers desc

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