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With SelectTag AS
     (SELECT DISTINCT PostTags.TagId as TagId, TagName
     FROM PostTags INNER JOIN (SELECT * FROM Tags WHERE 
     TagName = 'docker' or 
     TagName = 'terraform' or 
     TagName = 'elasticsearch' or 
     TagName = 'travis' or 
     TagName = 'kubernetes'
     ) as A on PostTags.TagId = A.Id)
     



SELECT * FROM SelectTag;

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edited jan 26

created jan 26 jon.doe41074