find tags that only differ by a .

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The Great Outdoors

Q&A for people who love being outdoors enjoying nature and wilderness, and learning about the required skills and equipment

select t.tagname , t.[Count],  t2.tagname, t2.[count]
from tags t
, tags t2
where t.tagname = replace(t2.tagname, '-', '.')
and t.id <> t2.id
order by t.tagname

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