## Anton.Sandbox

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Q&A for linguists, teachers and learners wanting to discuss the finer points of the Portuguese language

``````/* BEST TIME TO ASK QUESTIONS

The best time here is when the delay between a question and an accepted

On the graph, look for the value on the x-axis that
corresponds to the minimum value on y-axis.
That's the best time as defined above.

on Saturday at 1pm GMT. The asker had to wait for only 78 minutes.

Parameters:
- All: Include all users of only one specified by UserId
Values: 0 - show stats for one user, 1 - for all users
- Frequency: The scale of X-axis
Values: 1 - hours, 2 - day of week, 3 - both
- MaxTimeDiff: The cut off value for time difference. All time-to-answer
above this value will be excluded from the statistics.
Default value: 1440 min (24 hours).
- UserId: Whose stats to include in calculations. Matters only when All = 0.
Values: Your user ID or someone else's.
*/

DECLARE @Frequency int = ##Frequency:int?3##
DECLARE @MaxTimeDiff int = ##MaxTimeDiff:int?1440##
DECLARE @All int = ##All:int?1##
DECLARE @UsedId int = ##UserId:int##

;WITH tmp AS
(
SELECT x1 = q.ViewCount, x2 = q.Score,
Period = CASE @Frequency
WHEN 1 THEN DATEPART("hour", q.CreationDate)
WHEN 2 THEN DATEPART("weekday", q.CreationDate)
WHEN 3 THEN ROUND((CAST(DATEPART("weekday", q.CreationDate) AS numeric) +
CAST(DATEPART("hour", q.CreationDate) AS numeric) / 24), 2) END
FROM Posts q
LEFT OUTER JOIN Posts a ON q.AcceptedAnswerId = a.Id
AND q.OwnerUserId = CASE WHEN @All = 1 THEN q.OwnerUserId ELSE @UsedId END
)
SELECT Period, AVG(x1), AVG(x2)
FROM tmp
GROUP BY Period
ORDER BY Period``````

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