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Software Engineering

Q&A for professionals, academics, and students working within the systems development life cycle

WITH
 
  -- This table contains all the distinct date 
  -- instances in the data set
  dates(date) AS (
    SELECT DISTINCT CAST(CreationDate AS DATE)
    FROM Posts
    WHERE OwnerUserId = ##UserId##
  ),
   
  -- Generate "groups" of dates by subtracting the
  -- date's row number (no gaps) from the date itself
  -- (with potential gaps). Whenever there is a gap,
  -- there will be a new group
  groups AS (
    SELECT
      ROW_NUMBER() OVER (ORDER BY date) AS rn,
      dateadd(day, -ROW_NUMBER() OVER (ORDER BY date), date) AS grp,
      date
    FROM dates
  )
SELECT *
FROM groups
ORDER BY rn

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