Вопросы и ответы для программистов
select a.Id as link, q.Title as title, q.Tags as tags, a.Score as score from Posts q inner join Posts a on q.Id = a.ParentId and a.postTypeId = 2 and q.postTypeId = 1 where a.CommunityOwnedDate is null and a.OwnerDisplayName = '##UserName##' and a.OwnerUserId is null order by a.Score desc