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Вопросы и ответы о сайте для программистов

;  with badges_cte as
(SELECT TOP(##num?200##)
  b.UserId AS uid,
  sum(case when b.class = 1 then 1 else 0 end) AS gold,
  sum(case when b.class = 2 then 1 else 0 end) AS silver,
  sum(case when b.class = 3 then 1 else 0 end) AS bronze,
  count(b.Id) AS total
FROM Badges b INNER JOIN tags t ON t.tagname=b.name
GROUP BY b.UserId
)

SELECT
  RANK() OVER(ORDER BY gold DESC, silver DESC, bronze DESC, total DESC),
  uid AS [User Link], gold, silver, bronze, total
FROM badges_cte  
ORDER BY gold DESC, silver DESC, bronze DESC, total DESC

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created jul 30 19 Martin20528