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8 views

WITH VOTES_PRE AS( SELECT a.Id, a.CreationDate as acd, va...

jan 18
9 views

select posttypeid, count(viewcount) viewcount_nunnull fro...

jan 18
9 views

select count(viewcount) from posts where posttypeid in (2...

jan 18
9 views

SELECT a.Id as answer_id , q.CreationDate as question_dat...

jan 18
10 views

WITH VOTES_PRE AS( SELECT a.Id, a.CreationDate as acd, va...

jan 18
10 views

WITH VOTES_PRE AS( SELECT a.Id, a.CreationDate as acd, va...

jan 18
10 views

Select Id, DisplayName, Location from Users where Locatio...

jan 18
11 views

Select count(Id), Location from Users group by Location

jan 18
11 views

Select Id, DisplayName, Location from Users where Locatio...

jan 18
12 views

select top 10 Users.*, AmountOfQuestions from Users join ...

jan 18
11 views

select top 10 DisplayName, AccountId, Reputation, AmountO...

jan 18
11 views

select top 10 DisplayName, AccountId, Reputation, AmountO...

jan 18
11 views

select top 10 DisplayName, AccountId, Reputation, AmountO...

jan 18
11 views

select top 10 DisplayName, AccountId, Reputation, AmountO...

jan 18
13 views

select top 10 DisplayName, AccountId, Reputation, AmountO...

jan 18
13 views

select top 10 DisplayName, AccountId, AmountOfQuestions f...

jan 18
12 views

Select Name as "label name", count(distinct UserId) as "l...

jan 18
12 views

select DisplayName, AccountId, AmountOfQuestions from (se...

jan 18
13 views

select DisplayName, AccountId, AmountOfQuestions from (se...

jan 18
12 views

select count(Id) from Users where Location = 'Germany'

jan 18
12 views

select DisplayName, Location from Users where year(Creati...

jan 18
11 views

select count(Id) from Users where year(CreationDate) = 2015

jan 18
13 views

select DisplayName, Location from Users where year(Creati...

jan 18
12 views

select * from (select count(*) as AmountOfUsers from User...

jan 18
11 views

select * from (select count(*) as Users from Users) A cro...

jan 18
11 views

select * from (select count(*) as Users from Users) A cro...

jan 18
11 views

select * from (select count(*) as Users from Users) A cro...

jan 18
11 views

select * from (select count(*) as Users from Users) A cro...

jan 18
12 views

select * from (select count(*) as Users from Users) A cro...

jan 18
12 views

select * from (select count(*) as a from Users) A cross j...

jan 18

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queries

Q&A for students, teachers, and linguists wanting to discuss the finer points of the Russian language

3.9k questions

10k answers

26k comments

169 tags

jan 12 most recent