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Q&A for scientists using computers to solve scientific problems

SELECT 
ts.SourceTagName AS [TagName],
ts.TargetTagName AS [TagName],
* 
FROM TagSynonyms ts LEFT OUTER JOIN Tags t ON t.TagName=ts.TargetTagName
LEFT OUTER JOIN Tags t2 ON t2.TagName=ts.SourceTagName
WHERE t.Id IS NULL
  AND t2.Id IS NULL

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created jul 1 Martin20528