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Q&A for scientists using computers to solve scientific problems

-- Enter Query Title
-- Enter Query Description

SELECT TOP 100
  OwnerUserId as [User Link],
  SUM(Posts.Score) AS Score,
  Users.Reputation,
  COUNT(Posts.Id) AS Posts,
  CAST(Users.Reputation AS FLOAT)/COUNT(Posts.Id) AS Ratio
FROM
  Posts
INNER JOIN Users ON Users.Id = OwnerUserId
WHERE
  Users.Reputation >= 1000
GROUP BY
  OwnerUserId,
  Users.Reputation
HAVING
  COUNT(Posts.Id) > 50
ORDER BY
  Ratio DESC

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created feb 23 11 Renesis