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Select top N users by upvotes they received for their answers for a given tag located in the specified city or country

Q&A for science fiction and fantasy enthusiasts

-- Top Users by Country
-- Created by Mihai Todor (http://stackoverflow.com/users/1174378/mihai-todor)
/*
SELECT
    ROW_NUMBER() OVER(ORDER BY Reputation DESC) AS [#], 
    Id AS [User Link], 
    Reputation
FROM
    Users
WHERE
    LOWER(Location) LIKE LOWER('%##CountryName##%')
ORDER BY
    Reputation DESC;
*/

--SELECT TOP 10 * FROM Tags ORDER BY Count DESC

--SELECT * FROM TagSynonyms WHERE LOWER(SourceTagName) LIKE LOWER('%C++%') --ORDER BY Count DESC


DECLARE @Tag NVARCHAR(35) = ##Tag:string##;
DECLARE @Country NVARCHAR(100) = LTRIM(RTRIM(##Country:string##));
DECLARE @City NVARCHAR(100) = LTRIM(RTRIM(##City:string? ##));

SELECT COUNT(*)
FROM Posts AS p
INNER JOIN Posts AS a ON a.ParentId = p.id -- answers only
INNER JOIN PostTags AS pt ON p.Id = pt.PostId
INNER JOIN Tags AS t ON pt.TagId = t.Id
INNER JOIN Users AS u ON u.Id = a.OwnerUserId
WHERE a.PostTypeId = 2 -- answers only
AND t.TagName IN (
  SELECT @Tag
  UNION
  SELECT SourceTagName FROM TagSynonyms WHERE LOWER(SourceTagName) LIKE LOWER('%' + @Tag + '%')
  UNION
  SELECT TargetTagName FROM TagSynonyms WHERE LOWER(TargetTagName) LIKE LOWER('%' + @Tag + '%')
)
AND (
  LOWER(u.Location) LIKE LOWER('%' + @Country + '%')
  OR
  LOWER(u.Location) LIKE LOWER('%' + @City + '%')
  OR
  LOWER(u.AboutMe) LIKE LOWER('%' + @Country + '%')
  OR
  LOWER(u.AboutMe) LIKE LOWER('%' + @City + '%')
)
GROUP BY u.Id
ORDER BY SUM(a.Score) DESC

view current version

edited aug 2 16

created aug 2 16 Mihai.Todor