Q&A for information security professionals
SELECT ID, TagName INTO #MyTags FROM Tags WHERE --TagName = 'vim' --TagName = 'maxima' --TagName IN ('c++17', 'c++20') TagName IN ('okta') SELECT TOP 200 Posts.ID AS [Post Link], Posts.Tags AS [Tags], Posts.Score AS [Score] FROM Posts join PostTags ON PostTags.PostID = Posts.ID join Tags ON Tags.ID = PostTags.TagID WHERE TagID in (SELECT ID FROM #MyTags) ORDER BY Posts.Score DESC