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Q&A for professional and enthusiast programmers

-- Enter Query Title
-- Enter Query Description
SELECT TOP 100
    Id AS [User Link],
    Reputation
FROM Users U
    INNER JOIN (
        SELECT OwnerUserId, Cnt = Count(*)
        FROM Posts
        GROUP BY OwnerUserId
        HAVING Count(*) >= ##MinNumberOfPosts##
    ) P ON U.Id = P.OwnerUserId
ORDER BY Reputation DESC

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created sep 6 10 Peter Ajtai