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On avg how often are answers I give, accepted

Q&A for professional and enthusiast programmers

SELECT a.OwnerUserId AS [User Link],
    (CAST(Count(a.Id) AS float) / (SELECT Count(*) FROM Posts WHERE PostTypeId = 2) * 100) AS AcceptedPercentage
FROM
    Posts q
  INNER JOIN
    Posts a ON q.AcceptedAnswerId = a.Id
WHERE
    a.PostTypeId = 2
GROUP BY a.OwnerUserId
HAVING
    Count(a.OwnerUserId) > 10
ORDER BY AcceptedPercentage DESC

fork query

edited feb 20 20 maniero

created may 25 10 sam.saffron