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Q&A for professional and enthusiast programmers

select
  Rank() over (order by count(*) desc) as Rank,
  UserId as [User Link],
  count(*) as Count from badges
  where lower(Name) = lower(##Language1:string##)
  group by UserId
  order by count(*) desc;

fork query

edited mar 24 21

created mar 24 21 Bubbler