select distinct u.Id as [User Link], Reputation, DisplayN...


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distinct u.Id as [User Link], Reputation, DisplayName, WebsiteUrl, AboutMe, Views, COUNT(a.Id) AS [answer count]
from Users u
inner join Posts a on a.OwnerUserId = u.Id
inner join Posts q on a.ParentId = q.Id
and u.Reputation >= 1000    -- at least 1000 rep
and a.PostTypeId = 2        -- Answers ..
and q.tags LIKE '%<javascript>%'  -- to questions with the Javascript tag
GROUP BY, Reputation, DisplayName, WebsiteUrl, AboutMe, Views
order by COUNT(a.Id) DESC

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