Stack Overflow and shared tags


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Stack Overflow

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select  st.tagname [Tagname]
      , st.count [# Stack Overflow Questions]
      , ct.count [# Cooking Questions]
      , concat(''
              , ct.tagname
              , '|'
              , ct.tagname)  [Cooking Tag]
from tags st
inner join [].[dbo].tags ct on ct.tagname = st.tagname
order by st.count + ct.count desc

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