Q&A for computer enthusiasts and power users
SELECT TOP (##num?1000##) a.OwnerUserId AS [User Link], a.OwnerDisplayName, t.TagName, AVG(CAST(a.Score AS decimal)) AS [Average Score], SUM(a.Score) AS [Total Score], COUNT(a.Score) AS [Count] FROM Posts a INNER JOIN PostTags pt ON a.ParentId = pt.PostId INNER JOIN Tags t ON pt.TagId = t.Id GROUP BY a.OwnerUserId, a.OwnerDisplayName, t.TagName HAVING COUNT(a.Score)>=##min?50## ORDER BY AVG(CAST(a.Score AS decimal)) DESC