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Q&A for folks dedicated to a lifestyle that can be maintained indefinitely without depleting available resources

-- Enter Query Title
-- Enter Query Description

with
variants as (
  select *
  from (select replace(TagName, 'ou', 'o') as vname, * from tags) as r
  where vname != tagname
)

select tags.tagname
from tags, variants
where tags.tagname = variants.vname;

fork query

created aug 8 10 sth