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User Experience

Q&A for user experience researchers and experts

with posts_2010 as (
    select distinct owneruserid
    from posts
    where year(creationdate) = 2010
),
posts_2015 as (
    select distinct owneruserid
    from posts
    where year(creationdate) = 2015
)
select distinct top 10 u.displayname
from users u
join posts_2015 p15 on u.id = p15.owneruserid
left join posts_2010 p10 on u.id = p10.owneruserid
where p10.owneruserid is null
order by u.displayname;

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