select mm,cnt as curr,prev,round(100-cnt*100.00/prev,2) prc

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Woodworking

Q&A for professional and amateur woodworkers

select mm,cnt as curr,prev,round(100-cnt*100.00/prev,2) prc
  from (
   select mm,cnt,lag(cnt) over (order by mm) prev
     from (
      select year(creationDate) as yy, month(creationDate) as mm,
             count(1) as cnt
        from posts
       where PostTypeId between 1 and 2
       group by year(creationDate), month(creationDate)
   ) A
  ) A
 where cnt < prev
 order by mm

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